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In a biprism experimentn the distance be...

In a biprism experimentn the distance between second and eight dark fringes on the same side of central bright fringe is 3 mm. The fringe width is

A

1 mm

B

`0.5` mm

C

`1.5 mm`

D

2 mm

Text Solution

Verified by Experts

The correct Answer is:
B

`x_(8)-x_(2)=3 " "[ :.x_(n)=(2n-1) beta//2]`
`:. 7.5 beta-1.5 beta=3`
`:. beta=(3)/(6)=0.5 mm`
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NIKITA PUBLICATION-INTERFERENCE AND DIFFRACTION-MULTPLE CHOICE QUESTIONS
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