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In a biprism experimentn the distancce ...

In a biprism experimentn the distancce virtua images of the slit is `2.5 mm` and the eypiece is a distance of 1 m from the slits. If the fringe width is `0.3` mm then the frequency of sources of lights is

A

`4xx10^(14)Hz`

B

`2xx1^(15)Hz`

C

`4xx10^(12)Hz`

D

`2xx1^(12)Hz`

Text Solution

Verified by Experts

The correct Answer is:
A
`n=(V)/(lambda)=(v)/(d)(D)/(beta) " " ( :. lambda=d beta//D)`
`=(3xx10^(8)xx1)/(2.5xx10^(-3) xx0.3xx10^(-3))=4xx10^(14)Hz`
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