In a biprism experimentn the distance between slite and epepiece is 1m. If the convex lens is interposed at a distance of 30 cm from the slit, then the size of the magnified image is `0.7` mm. The distance between the two virtual images of the slits will be

Options

A. `0.1 mm`
B. `0.2 mm`
C. `0.3 mm`
D. `0.4 mm`

Answer

C

Explanation

`("Size of image")/("Size of aboject")=("Distance of image")/("Distance of object")`
`implies(d_(1))/(d)=(v)/(u)`
`:.d=(u)/(v)d_(1)=(30xx0.7)/(70)=0.3` mm