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The distance between the first and the s...

The distance between the first and the sixth minima in the diffraction pattern of a single slit is 0.5 mm. The screen is 0.5 m away from the slit. If the wavelength of light used is 5000 Å. Then the slit width will be

A

`2.5mm`

B

`5 mm`

C

`1.25 mm`

D

`1 mm`

Text Solution

Verified by Experts

The correct Answer is:
A
`x_(6)-x_(1)=(5Dlamda)/(a)`
`:.a=(5Dlamda)/(x_(6)xxx_(1))=(5xx0.5xx5xx10^(-7))/(0.5xx10^(-3))`
`=25xx10^(-4)m`
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