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The diameter of an eye lens is 2.5xx10^(...

The diameter of an eye lens is `2.5xx10^(-3)` m and the refractive index of the eye fluid is `1.44`. The resolving power of the eye for light of wavelenght `5000Å` will be

A

`1.07'`

B

`0.86'`

C

`1.71'`

D

`1.14'`

Text Solution

Verified by Experts

The correct Answer is:
C
`theta=(1.22lamda)/(D)=(1.22xx5xx10^(-7)xx180xx60)/(2.5xx10^(-3)xx1.44xx3.14)min`
R.P. `=(1)/(theta)=1.71`
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