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In the Young's experiment, the distance ...

In the Young's experiment, the distance between slit and screen is doubled and the distance between the two slits is reduced to half. The fringe widht is

A

`3 beta`

B

`2 beta`

C

`4 beta`

D

`6 beta`

Text Solution

Verified by Experts

The correct Answer is:
A

`D_(2)=2D_(1),d_(2)=(d_(1))/(2),beta_(2)-beta_(1)=?`
`betaprop(D)/(d)`
`:.(beta_(2))/(beta_(1))=(D_(2))/(D_(1))xx(d_(1))/(d_(2))`
`beta_(2)=(2D_(1))/(D_(1))xx(d_(1))/((d_(1))/(2))xxbeta_(2)=4beta_(1)`
`:.beta_(2)-beta_(1)=4beta_(1)-beta_(1)=3beta_(1)=3beta`
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