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A central fringe of interference pattern...

A central fringe of interference pattern produced by light of wavelength `6000 Å` is shifted to the position of 5th bright fringe by introducing thin film of `mu = 1.5`. Calculate thickness of the film.

A

`6xx10^(-4) mm`

B

`6xx10^(-4) m`

C

`6xx10^(-4)m`

D

3 cm

Text Solution

Verified by Experts

The correct Answer is:
C
`lamda=6000A^(@),Deltabeta=5beta,mu=1.5t=?`
`Deltabeta=(beta)/(lamda)(mu-1)t`
`5beta=(beta)/(6xx10^(-7))(1.5-1)t`
`t=(30xx30)/(0.5)`
`=60xx10^(-7)m`
`=6xx10^(-4)cm`
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