If the ratio of amplitude of two waves is `4:3`, then the ratio of maximum and minimum intensity is

Options

A. `16:9`
B. `9:16`
C. `1:49`
D. `49:1`

Answer

D

Explanation

`(a_(1))/(a_(2))=(4)/(5)`
`a_(2) =(3a_(1))/(4)`
`(I_("max"))/(I_("min"))+((a_(1)+a_(2))^(2))/((a_(1)-a_(2))^(2))=((a_(1)+(3a_(1))/(4))^(2))/((a_(1)-(3a_(1))/(4))^(2))=(49)/(1)`