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In an interference experiment with a bip...

In an interference experiment with a biprism, the distance of the slits from the screenn is increased by 25% annd the separation between the slits is halved. If X represents the original fringe width, the new fringe width will be

A

`2.5X`

B

`1.5X`

C

`2X`

D

`4X`

Text Solution

Verified by Experts

The correct Answer is:
A

`D_(2)=1.25 D_(1) D_(2)=(d_(2))/(2), beta_(2)= b ? beta_(1)=x`
`b=(D)/(d)`
`:. (beta_(2))/(beta_(1))=(D_(2))/(D_(1))xx(d_(1))/(d_(2))`
`beta_(2)=(1.25 D_(1))/(D_(1))xx (d_(2) xx 2)/( d_(1)) xx beta_(1)`
`beta_(2)=2.5 beta_(1) = 2.5 X`
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