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In young double slit experiment the r...

In young double slit experiment the ratio of intentsities of bright and dark bands is 16 which means

A

the ratio of their amplitudes is 5

B

intensites of individual source are 25 and 9 unit respectively

C

the ratio of their amplitudes is 4

D

intensities of individual sources are 4 and 3 units respectively

Text Solution

Verified by Experts

The correct Answer is:
B

`(I_("max"))/(I_("min")) =((a_(1)+a_(2))^(2))/((a_(1)-a_(2))^(2))=(16)/(1)`
`=:. (a_(1))/(a_(2))=(5)/(3)`
But `I propa^(2)`
`:. (I_(1))/( I_(2))=(a_(1)^(2))/(a_(2)^(2))=(25)/(9)`
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