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In a hydrogen atom, the distance between...

In a hydrogen atom, the distance between the electron and proton is `2.5 xx 10^(-11)m`. The electricl force of attraction between then will be

A

`6.3xx10^(-8)N`

B

`8.2xx10^(-8)N`

C

`9.6xx10^(-8)N`

D

`12.2xx10^(-8)N`

Text Solution

Verified by Experts

The correct Answer is:
B
`F=1/(4piin_(0))xx(q_(1)q_(2))/r^(2)`
`=(9xx10^(9)xx1.6xx1.6xx10^(-38))/((5.3xx10^(-11))^(2))`
`=8.2xx10^(-8)N`
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