If the distance between two equal point charges is doubled and their individual charges are also doubled, what would happen to the force between them?

Options

A. halved
B. remain same
C. doubled
D. becomes zero

Answer

B

Explanation

`r_(2)=2r_(1), q'_(2)=2q_(2)andq'_(1)=2q_(1), F'=?`
`Fprop(q'_(1)q'_(2))/r^(2)`
`therefore" "(F')/(F)=(q'_(1)q'_(2))/(q_(1)q_(2))xx(r_(1)/r_(2))^(2)`
`F'=(2q_(1)2q_(2))/(q_(1)q_(2))xx(r_(1)/(2r_(1)))^(2)F`
`F' = F`