The electric field at a point due to a point charge is `20 NC^(-1)` and electric potential at that point is `10 JC^(-1)`. Calculate the distance of the point from the charge and the magnitude of the charge.

Options

A. 2500 V
B. 22500 V
C. 2000 V
D. 20500 V

Answer

B

Explanation

`V=1/(4piin_(0))xxq/r=(9xx10^(9)xx25xx10^(-6))/10`
= 22500 V