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The surface density of charge on the ear...

The surface density of charge on the earth's surface is `2.65xx10^(-9)C//m^(2)`. If the radius of the earth is 6400 km then the charge carried by the earth is

A

`1.363xx10^(6)C`

B

`1.364xx10^(9)C`

C

`3.364xx10^(6)C`

D

`2.396xx10^(6)C`

Text Solution

Verified by Experts

The correct Answer is:
A
`sigma=q/(4piR^(2))`
`therefore" "q=sigma4piR^(2)`
`=2.65xx10^(-9)xx4xx3.14xx(6.4xx10^(6))^(2)`
`=1.363xx10^(6)C`
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