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In an electron gun, the electrons are ac...

In an electron gun, the electrons are accelerated by the potential `V`. If the `e` is the charge and `m` is the mass of the electron, then the maximum velocity of these electrons will be

A

`sqrt((eV)/(m))`

B

`sqrt((e)/(Vm))`

C

`sqrt((2eV)/(m))`

D

none of these

Text Solution

Verified by Experts

The correct Answer is:
C
`W=qV" ""i.e. "1/2mv^(2)=qV`
`therefore" "v=sqrt((2qV)/m)=sqrt((2eV)/m)" "(thereforeq=e)`
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