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A cube of marble of each side 5m long is...

A cube of marble of each side 5m long is placed in electric field of intensity of `3kV//m`. The amount of electrostatic energy stored in marble of dielectric constant 8 is

A

`39.82xx10^(-3)J`

B

`4.982xx10^(-2)J`

C

`9.832xx10^(-3)J`

D

`8.392xx10^(-3)J`

Text Solution

Verified by Experts

The correct Answer is:
A
`u=1/2in_(0)kE^(2)`
`therefore" ""Energy"=1/2in_(0)kE^(2)xx"volume"`
`=(8.85xx10^(-12)xx8xx(3xx10^(3))^(2)xx(5)^(3))/2`
`=39.82xx10^(-3)J//m^(3)`
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NIKITA PUBLICATION-ELECTROSTATICS-Multiple Choice Questions
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