The ratio of polarisation to electric intensity is

Options

A. electric permitivity
B. electric susceptibility
C. electric flux
D. electric torque

Answer

To solve the question regarding the ratio of polarization to electric intensity, we will follow these steps:

### Step-by-Step Solution:

1. **Understanding Polarization and Electric Intensity**:
- Polarization (P) is defined as the dipole moment per unit volume of a dielectric material. It represents how much the material becomes polarized in response to an electric field.
- Electric intensity (E), also known as electric field strength, is the force experienced per unit charge in an electric field.

2. **Establishing the Ratio**:
- The question asks for the ratio of polarization (P) to electric intensity (E). Mathematically, this can be expressed as:
\[ \text{Ratio} = \frac{P}{E} \]

3. **Relating to Susceptibility**:
- In electrostatics, the ratio of polarization to electric field intensity is related to electric susceptibility (χ). Electric susceptibility quantifies how easily a material can be polarized by an electric field.
- The relationship can be expressed as:
\[ \frac{P}{E} = \chi \]
- Here, χ (chi) represents the electric susceptibility of the material.

4. **Conclusion**:
- Therefore, the ratio of polarization to electric intensity is equal to the electric susceptibility of the material:
\[ \frac{P}{E} = \chi \]

### Final Answer:
The ratio of polarization to electric intensity is the electric susceptibility (χ).

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