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The area of each plate of parallel plate...

The area of each plate of parallel plate condenser is `20cm^(2)` and distance them is 2mm. It stores the energy if 5J. The energy density of electric field between its plates is

A

`250xx10^(6)J//m^(3)`

B

`1.25xx10^(6)J//m^(3)`

C

`2xx10^(6)J//m^(3)`

D

`4xx10^(6)J//m^(3)`

Text Solution

Verified by Experts

The correct Answer is:
B
`A=20Cm^(2),d=2mm,U=5J,u=?`
`u=("energy")/("volume")=U/(A.d)=5/(20xx10^(-4)xx2xx10^(-3))`
`=1.25xx10^(6)J//m^(3)`
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