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Find the capacitance of a capacitor havi...

Find the capacitance of a capacitor having a charge of `6xx10^(-7)C` and energy of `4.5xx10^(-4)J`

A

`4xx10^(-10)F`

B

`5xx10^(-10)F`

C

`7xx10^(-10)F`

D

`9xx10^(-10)F`

Text Solution

Verified by Experts

The correct Answer is:
A
`E=Q^(2)/(2C)`
`therefore" "C=Q^(2)/(2E)=((6xx10^(-7))^(2))/(2xx4.5xx10^(-4))=4xx10^(-10)F`
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