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A condenser of capacitance 6muF was orig...

A condenser of capacitance `6muF` was originally charged to 10 V. Now potential difference is made 20 V. The increase in potential energy is

A

`2xx10^(-4)J`

B

`3xx10^(-4)J`

C

`6xx10^(-4)J`

D

`9xx10^(-4)J`

Text Solution

Verified by Experts

The correct Answer is:
D
`deltaE=1/2CV_(2)^(2)-1/2CV_(1)^(2)`
`=C/2(V_(2)^(2)-V_(1)^(2))`
`=(6xx10^(-6))/2(400-100)`
`=9xx10^(-4)J`
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NIKITA PUBLICATION-ELECTROSTATICS-Multiple Choice Questions
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  10. The equivalent capacity of n identical condensers each of capacity C c...

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  12. In series combination of condensers, potential is distributed in

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  13. If the number of condensers are connected one after another then this ...

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  14. If the number of condensers are connected in parallel then

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  15. The equivalent capacity of number of condensers can be increased if th...

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  16. The resultant capacity of n condensers of capacitances C(1),C(2).........

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  17. Write the equivalent capacitance of a number of identical capacitors c...

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  18. The resultant capacity of number of condensers connected in parallel i...

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  19. In parallel combination of condensers charge is distributed in

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