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If two capacitors 2muF and 6muF are put ...

If two capacitors `2muF and 6muF` are put in series. The effective capacitance of the system will be

A

`8muF`

B

`4muF`

C

`3muF`

D

`3//2muF`

Text Solution

Verified by Experts

The correct Answer is:
D
`C_(s)=(C_(1)C_(2))/(C_(1)+C_(2))=(2xx6)/(2+6)=3/2muF`
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