Two capacitances of capacity `C_(1)`and `C_(2)` are connected in series and potential difference `V` is applied across it. Then the potential difference across `C_(1)` will be

Options

A. `VC_(2)/C_(1)`
B. `(V(C_(1)+C_(2)))/C_(1)`
C. `(VC_(2))/((C_(1)+C_(2)))`
D. `(VC_(1))/((C_(1)+C_(2)))`

Answer

C

Explanation

`V_(1)=Q/C_(1)=(C_(s)V)/C_(1)=((C_(1)C_(2))/(C_(1)+C_(2)))V/C_(1)=(VC_(2))/(C_(1)+C_(2))`