Two capacitors having capacities `C_(1) and C_(2)` are charged to voltages `V_(1) and V_(2)` respectively. There will be no exchange of energy in connecting them in parallel, if

Options

A. `C_(1)=C_(2)`
B. `C_(1)V_(1)=C_(2)V_(2)`
C. `V_(1)=V_(2)`
D. `(C_(1)V_(1))/(C_(2)V_(2))`

Answer

C

Explanation

Loss of energy = `1/2((C_(1)C_(2))/(C_(1)+C_(2)))(V_(1)-V_(2))^(2)`
If `V_(1) = V_(2)`, loss of energy = 0