Two capacitors of `3 pF` and `6pF` are connected in series and a potential difference of `5000 V` is applied across the combination. They are then disconnected and reconnected in parallel. The potential between the plates is

Options

A. 2250 V
B. 1111 V
C. `2.25xx10^(6)V`
D. `1.1xx10^(6)V`

Answer

B

Explanation

`Q=CsV=((C_(1)C_(2))/(C_(1)+C_(2)))V=10^(-8)C`
In parallel, `V=Q/(C_(1)+C_(2))=10^(-8)/(9xx10^(-12))=1111V`