The p.d. across the capacitance of `2muF` in the figure along with is

Options

A. 10 V
B. 60 V
C. 28 V
D. 56 V

Answer

B

Explanation

From figure, equivalent capacity of `3muF, 6muF and 3muF` condensers is `C_(p)=12muF`.
Now, `C_(p)` and condenser of `2muF` are in series. Thus, p.d. across `2muF` condenser is,
`V=((VC_(p))/(C_(1)+C_(p)))=(70xx12xx10^(-6))/(14xx10^(-6))=60V`