A circuit is shown in the figure below. Find out the charge of the condenser having capacity `5muF`

Options

A. `4.5muC`
B. `9muC`
C. `7muC`
D. `30muC`

Answer

B

Explanation

From figure, charge on condenser of capacity `3muF` is,
`Q_(1)=C_(1)V=3xx10^(-6)xx6=18xx10^(-6)C`.
Thus, p.d. across `C_(1)` is,
`V_(1)=(VC_(p))/(C_(1)+C_(p))" ""where"" "C_(p)=2+5=7muF`
`=(7xx6)/10=4.2V`
Thus, p.d. across `C_(p)` is, 1.8 V
Now, charge on `5muF` condenser is,
`Q_(2)=5xx10^(-6)xx1.8=9muC`