The area of the plates of a parallel plate condenser is `A` and the distance between the plates is `10 mm`. There are two dielectric sheets in it, one of dieectirc constant `10` and thickness `6 mm` an dthe other of dielectric constant `5` and thickness `4 mm`. the capacity of the condenser is

Options

A. `5000/7in_(0)A`
B. `500/7in_(0)A`
C. `50/7in_(0)A`
D. `50/14in_(0)A`

Answer

A

Explanation

`C=(in_(0)A)/(t_(1)/K_(1)+t_(2)/K_(2))=(in_(0)A)/((6xx10^(-3))/10+(4xx10^(-3))/5)`
`C=5000/7in_(0)A`