An electric cable of diameter 10 cm runs under water (k for water = 81) for a distance of 5 km. If the cable carries a charge of 0.01 C on its surface. The electric intensity at a distance of 95 cm from the surface of the cable is

Options

A. `2.4xx10^(2)N//C`
B. `4.4xx10^(2)N//C`
C. `4.4xx10^(3)N//C`
D. `4.4xx10^(-2)N//C`

Answer

B

Explanation

`E=1/(4piepsi_(0)k)(2q)/r=1/(4piepsi_(0)k)(2Q)/(rL)`
`=(9xx10^(9)xx2xx0.01)/(81xx1xx5xx10^(3))=4.4xx10^(2)N//C.`