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Find the electric field intensity due to...

Find the electric field intensity due to a positively charged conducting cylinder with radius 1 cm and surface charge density `10^(-9)C//m^(2)`, at a point at a distance of 2 m from the axis of cylinder. The dielectric constant of the medium surrounding the cylinder is 2.

A

`0.28V//m`

B

`1.28V//m`

C

`2.28V//m`

D

`1.00V//m`

Text Solution

Verified by Experts

The correct Answer is:
A

`E=(sigmaR)/(epsi_(0)kr)=(10^(-9)xx1xx10^(-12))/(8.85xx10^(-12)xx2xx2)=0.28V//m.`
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