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A closed conducting sphere is positively...

A closed conducting sphere is positively charged such that the surface charge density is `17.7xx10^(-12)C//m^(2)`. If the dielectric constant of the medium surrounding the conductor is 100, then electric field intensity at a point just outside it will be

A

`1.02 V//m`

B

`0.02 V//m`

C

`1.22 V//m`

D

`2.22 V//m`

Text Solution

Verified by Experts

The correct Answer is:
B
`E=sigma/(epsi_(0)k)=(17.7xx10^(-12))/(8.85xx10^(-12)xx100)=0.02V//m.`
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