The cell membrane of a resting nerve in ...

The cell membrane of a resting nerve in a human body has a thickness of 75 Å. If potential difference between the two sides of membrace is 0.06 V. Then intensity of electric field is

`8xx10^(6)V//m`

`4xx10^(6)V//m`

`8xx10^(-6)V//m`

`4xx10^(-6)V//m`

Text Solution

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The correct Answer is:

`E=V/d=0.06/(75xx10^(-10))=8xx10^(6)V//m.`

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