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A capacitor of 20 muF is charged to 500 ...

A capacitor of `20 muF` is charged to `500` volts and connected in parallel ith another capacitor of `10 muF` and charged to `200` volts. The common potential is

A

500V

B

400V

C

300V

D

200V

Text Solution

Verified by Experts

The correct Answer is:
B
`C_(1)=20mF,V_(1)=500V,`
`C_(2)=10mF,V_(2)=200V`
V = ?
`V=(C_(1)V_(1)+C_(2)V_(2))/(C_(1)+C_(2))`
`=(20xx10^(-6)xx500+10xx10^(-6)xx200)/(30xx10^(-6))`
= 400 V
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