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A charged oil drop is suspended in a uni...

A charged oil drop is suspended in a uniform filed of `3xx10^4 v//m` so that it neither falls nor rises. The charge on the drop will be (Take the mass of the charge `=9.9xx10^-15kg` and `g=10m//s^2`)

A

`3.3xx10^(-18)C`

B

`3.2xx10^(-18)C`

C

`1.6xx10^(-18)C`

D

`4.8xx10^(-18)C`

Text Solution

Verified by Experts

The correct Answer is:
A
F = mg = qE
`therefore" "q=(mg)/E=(9.9xx10^(-15)xx10)/(3xx10^(4))`
`=3.3xx10^(-18)C`
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