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If A is the area of each plate, charge o...

If A is the area of each plate, charge on it is q and potential difference is V then the distance between the parallel plate capacitor is

A

`(epsi_(0)AV)/(2q)`

B

`(epsi_(0)AV)/(q)`

C

`(2epsi_(0)AV)/(q)`

D

`(AV)/(q)`

Text Solution

Verified by Experts

The correct Answer is:
B
`V=E*d`
`d=V/E=V/(sigma/epsi_(0))`
`=(V/q)/(Aepsi_(0))=(VAepsi_(0))/q`
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