The electric field intensity at point near and outside the surface of a charged conductor of any shape is `E_(1)` the electric field intensity due to uniformly charged infinite thin plane sheet is `E_(2)` the relation between `E_(1)` and `E_(2)` is

Options

A. `2E_(1)=E_(2)`
B. `E_(1)=E_(2)`
C. `E_(1)=2E_(2)`
D. `E_(1)=4E_(2)`

Answer

C

Explanation

`E_(1)/E_(2)=((sigma)/(in_(0)k))/((sigma)/(2in_(0)k))=2/1" "i.e.,E_(1)=2E_(2)`