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A capacitor C(1)=4mu F is connected is...

A capacitor `C_(1)=4mu` F is connected is series with another capacitor `C_(2)=1mu`F the combination is connected across DC source of 200 V the ratio of potential across `C_(2)` to `C_(1)` is

A

`2 : 1`

B

`4 : 1`

C

`8 : 1`

D

`16 : 1`

Text Solution

Verified by Experts

The correct Answer is:
B
`V_(2)=((C_(1))/(C_(1)+C_(2)))V" "&" "V_(1)=(C_(2)/(C_(1)+C_(2)))V`
`therefore" "V_(2)/V_(1)=C_(1)/C_(2)=4/1.`
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