A conductor of length of l and area of cross section A has n number of electrons per unit volume of the conductor. The total charge carried by the conductor is

Options

A. nA/e
B. `(e)/(nAl)`
C. `(nAl)/(e)`
D. `n*e`

Explanation

To find the total charge carried by a conductor of length \( L \) and cross-sectional area \( A \) with \( n \) number of electrons per unit volume, we can follow these steps:

### Step-by-Step Solution:

1. **Determine the Volume of the Conductor**:
The volume \( V \) of the conductor can be calculated using the formula:
\[ V = A \times L \]
where \( A \) is the area of cross-section and \( L \) is the length of the conductor.

2. **Calculate the Total Number of Electrons**:
The total number of electrons \( N_{\text{total}} \) in the conductor can be found by multiplying the number of electrons per unit volume \( n \) by the volume \( V \):
\[ N_{\text{total}} = n \times V = n \times (A \times L) \]

3. **Charge of a Single Electron**:
The charge of a single electron \( e \) is approximately \( 1.6 \times 10^{-19} \) coulombs.

4. **Calculate the Total Charge**:
The total charge \( Q \) carried by the conductor can be calculated by multiplying the total number of electrons \( N_{\text{total}} \) by the charge of a single electron \( e \):
\[ Q = N_{\text{total}} \times e = (n \times A \times L) \times e \]

5. **Final Expression for Total Charge**:
Therefore, the total charge \( Q \) carried by the conductor is given by:
\[ Q = n \times A \times L \times e \]

### Final Answer:
The total charge carried by the conductor is:
\[ Q = n \times A \times L \times e \]