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There is a current of 0.21 A in a copper...

There is a current of 0.21 A in a copper wire of area of cross section `10^(-6)m^(2)`. If the number of electrons per `m^(3)` is `18.4xx10^(28)` then the drift velocity is ( `e=1.6xx10^(-19)C`)

A

`1.562xx10^(-5)m//s`

B

`2xx10^(-5)m//s`

C

`0.64xx10^(5)m//s`

D

`1xx10^(5)m//s`

Text Solution

Verified by Experts

The correct Answer is:
A
`v_(d)=(I)/( nA e)`
`= (0.21)/(8.4xx10^(28)xx10^(-6)xx1.6xx10^(-19))`
`=1.562xx10^(-5) m//s`
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