A metal wire of cross-sectional area 1m ...

A metal wire of cross-sectional area `1m m^(2)` contains `5xx10^(22)` electrons per `cm^(3)` . If the electrons move along the wire with average drift velocity `1m m//s`, then the current in the wire is (`e=1.6xx10^(-19)C`)

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The correct Answer is:

`v_(d)=(I)/(n A e)`
`:.I=v_(d) nA e`
`=1xx10^(-3)xx5xx10^(22)xx10^(6)xx10^(-6)xx1.6xx10^(-19)`
`= 8A`

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