Resistors of 1, 2, 3 ohm are connected in the form of a triangle. If a 1.5 volt cell of negligible internal resistance is connected across 3 ohm resistor, the current flowing through this resistance will be

Options

A. 0.25A
B. 0.5A
C. 1.0A
D. 1.5A

Answer

B

Explanation

The effective resistance of `1Omega, 2 Omega` and `3 Omega` is ,
`R=1.5 Omega`
Now, `I=(E)/(R+r)=(1.5)/(1.5+0)= 1 A`
Thus, current through `3 Omega` resistor is 0.5 A