Resistances of 6Omega each are connected...

Resistances of `6Omega` each are connected in the manner shown in the following figure. The potential difference `V_(p)-V_(q) ` is

13.6V

17.2V

Text Solution

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The correct Answer is:

From figure, effective resistance of network is ,
`R=2+4=6Omega`
Thus, `V_(P)-V_(Q)=IR=0.5xx6=3V`

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