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The internal resistance of the cell can ...

The internal resistance of the cell can be determined by,

A

ohm meter

B

galvanometer

C

voltmeter

D

potentiometer

Text Solution

Verified by Experts

The correct Answer is:
D
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The internal resistance of a cell is determined by using a potentiometer. In an experimetn, an external resistance of 60 Omega is used across the given cell. When the key is closed, the balance length on the potentiometer decreases form 72 cm to 60 cm. calculate the internal resistance of the cell.

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NIKITA PUBLICATION-CURRENT ELECTRICITY-Multiple Choice Questions
  1. The balancing lengths for the cells of e.m.f. E(1) and E(2) are l(1)...

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  2. The equation, ( E(1))/(E(2))= (l(1)+l(2))/(l(1)-l(2)), is used to com...

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  3. The internal resistance of the cell can be determined by,

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  4. The unit of potential gradient is

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  5. In comparing e.m.f. of two cells by a potentiometer balance point is o...

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  6. The sensitivity of the potentiometer can be increased by

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  7. Which of the following can cause the null point of a potentiometer to ...

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  8. When null point is obtained in the potentiometer the current is draw...

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  9. Potentiometer was first invented by

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  10. In the construction of potentiometer, the length of wire used is

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  11. A potentiometer is more sensitive when

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  12. Instead of voltmeter, potentiometer is always used to measure e.m.f. ...

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  13. The potentiometer wire of resistance R is connected in series with a c...

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  14. Potentiometer is used to

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  15. The internal resistance of a cell by potentiometer is given by

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  16. In potentiometer experiment to determine internal resistance of the ce...

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  17. The current, in a potentiometer wire of 100 cm length, is adjusted to ...

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  18. In given figure, the potentiometer wire AB has a resistance of 5 Omeg...

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  19. The wire of potentiometer has resistance 4 Omega and length 1m. It i...

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  20. A potentiometer has a uniform wire of length 10m and resistance 5 Ome...

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