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The current, in a potentiometer wire of ...

The current, in a potentiometer wire of 100 cm length, is adjusted to give a null point at 5 cm with standard cell of e.m.f. 1.018 V. The e.m.f. of cell which gives null point of 60 cm is

A

1.221V

B

2.22V

C

3.22V

D

4.22V

Text Solution

Verified by Experts

The correct Answer is:
A

`(E_(1))/(E_(2))=(l_(1))/(l_(2))`
`:.E_(2)=(l_(2))/(l_(1))E_(1)=(60xx10^(-2)xx1.018)/(50xx10^(-2))=1.221V`
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NIKITA PUBLICATION-CURRENT ELECTRICITY-Multiple Choice Questions
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  2. In potentiometer experiment to determine internal resistance of the ce...

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  4. In given figure, the potentiometer wire AB has a resistance of 5 Omeg...

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  5. The wire of potentiometer has resistance 4 Omega and length 1m. It i...

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  6. A potentiometer has a uniform wire of length 10m and resistance 5 Ome...

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  7. A voltmeter has a resistance of 50 Omega is connected across a cell ...

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  8. With a potentiometer null point were obtained at 140 cm and 180 cm w...

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  9. In a potentiometer experiment it is found that no current passes throu...

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  10. The potential gradient along the length of a uniform wire is 5 V/m. Th...

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  11. In figure AB is a potentiometer wire of length 10 m and resistance 1...

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  12. In figure, AB is a potentiometer wire, length 10 m and resistance 2 Om...

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  14. In the adjacent circuit the ammeter reads 5.0 A and voltmeter reads 20...

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  15. Following are the readings of potential and current through a specimen...

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  16. In a potentiometer experiment the balancing length is 8 m, when the tw...

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  17. Six cells each of e.m.f. 2 V and internal resistance 0.1Omega are conn...

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  18. Find the equivalent resistance of the network given in the figure,

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