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The internal resistance of a primary cel...

The internal resistance of a primary cell is `4 Omega` . It generates a current of 0.2 A in a external circuit of `21Omega` . The rate at which electric energy is consumed in providing the current is

A

1 J/s

B

2 J/s

C

1.5 J/s

D

2.5 J/s

Text Solution

Verified by Experts

The correct Answer is:
A

`P=(W)/(t)=I^(2)(R+r)=1J//s`
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