Home
Class 12
PHYSICS
The resistance of a conductor is 5Omega ...

The resistance of a conductor is `5Omega` at `50^(@)`C and `6Omega` at `100^(@)C`. The resistance at `0^(@)C` is

A

`2Omega`

B

`4 Omega`

C

`2.5Omega`

D

`4.5 Omega`

Text Solution

AI Generated Solution

The correct Answer is:
To find the resistance of a conductor at 0°C given its resistance at two different temperatures, we can use the formula that relates resistance and temperature: \[ R_t = R_0 (1 + \alpha \Delta T) \] Where: - \( R_t \) is the resistance at temperature \( t \) - \( R_0 \) is the resistance at 0°C - \( \alpha \) is the temperature coefficient of resistance - \( \Delta T \) is the change in temperature from 0°C ### Step 1: Set up the equations From the problem, we have: - \( R_{50} = 5 \, \Omega \) at \( 50°C \) - \( R_{100} = 6 \, \Omega \) at \( 100°C \) We can set up two equations based on the formula: 1. For \( 50°C \): \[ 5 = R_0 (1 + \alpha (50 - 0)) \quad \text{(Equation 1)} \] 2. For \( 100°C \): \[ 6 = R_0 (1 + \alpha (100 - 0)) \quad \text{(Equation 2)} \] ### Step 2: Rearranging the equations From Equation 1: \[ 5 = R_0 (1 + 50\alpha) \] \[ 5 = R_0 + 50 R_0 \alpha \quad \text{(Rearranging)} \] From Equation 2: \[ 6 = R_0 (1 + 100\alpha) \] \[ 6 = R_0 + 100 R_0 \alpha \quad \text{(Rearranging)} \] ### Step 3: Express \( R_0 \alpha \) Now, we can express \( R_0 \alpha \) from both equations: From Equation 1: \[ 50 R_0 \alpha = 5 - R_0 \quad \Rightarrow \quad R_0 \alpha = \frac{5 - R_0}{50} \quad \text{(Equation 3)} \] From Equation 2: \[ 100 R_0 \alpha = 6 - R_0 \quad \Rightarrow \quad R_0 \alpha = \frac{6 - R_0}{100} \quad \text{(Equation 4)} \] ### Step 4: Equate the two expressions for \( R_0 \alpha \) Set Equation 3 equal to Equation 4: \[ \frac{5 - R_0}{50} = \frac{6 - R_0}{100} \] ### Step 5: Cross-multiply and solve for \( R_0 \) Cross-multiplying gives: \[ 100(5 - R_0) = 50(6 - R_0) \] \[ 500 - 100 R_0 = 300 - 50 R_0 \] Rearranging: \[ 500 - 300 = 100 R_0 - 50 R_0 \] \[ 200 = 50 R_0 \] \[ R_0 = \frac{200}{50} = 4 \, \Omega \] ### Conclusion The resistance at \( 0°C \) is \( R_0 = 4 \, \Omega \). ---

To find the resistance of a conductor at 0°C given its resistance at two different temperatures, we can use the formula that relates resistance and temperature: \[ R_t = R_0 (1 + \alpha \Delta T) \] Where: - \( R_t \) is the resistance at temperature \( t \) - \( R_0 \) is the resistance at 0°C - \( \alpha \) is the temperature coefficient of resistance ...
Promotional Banner

Topper's Solved these Questions

  • CURRENT ELECTRICITY

    NIKITA PUBLICATION|Exercise Multiple Choice Questions|314 Videos
  • COMMUNICATION SYSTEMS

    NIKITA PUBLICATION|Exercise Multiple Choice Questions (Examples for Practice)|8 Videos
  • ELASTICITY

    NIKITA PUBLICATION|Exercise MCQ|314 Videos

Similar Questions

Explore conceptually related problems

If the resistance of a conductor is 5 Omega at 50^(@)C and 7Omega at 100^(@)C then the mean temperature coefficient of resistance of the material is

The resistance of a wire is 5 ohm at 50^@C and 6 ohm at 100^@C . The resistance of the wire at 0^@C will be

The resistance of a platinum resistance thermometer is 3.14 Omega at 40^(@)C and 3.76 Omega at 100^(@)C . Calculate the temperature coefficient of resistance of platinum. What will be its resistance when the thermometer is immersed in melting ice ?

The resistance of a coi is 4.2Omega at 100^(@)C and the temperature coefficient of resistance of its material is (0.004)/(.^(@)C) . Its resistance at 0^(@)C is

The resistance of a conductor at 15^(@)C is 16 Omega and at 100^(@)C is 20 Omega . What will be the temperature coefficient of resistance of the conductor ?

The rsistance of a conductor at 20^(@)C is 3.15 Omega and at 100^(@)C is 3.75 Omega . Determine the temperature coefficient of resistance of the conductor. What will be the resistance of the conductor at 0^(@)C ?

A conducting wire has a resistance of 5 Omega "at" 0^@C and 5.6 Omega "at" 100 ^@C . When the wire is inserted in a hot bath with temperature T^@C , its resistance is 5.9 Omega . What is the value of T ?

The resistance of a certain paltinum resistance thermomter is found to be 2.56 Omega at 0^(@)C and 3.56 Omega at 100^(@)C . When the thermometer is immersed in a given liquid, its resistance is observed to be 5.06 Omega . The temperature of the liquid

NIKITA PUBLICATION-CURRENT ELECTRICITY-Multiple Choice Questions
  1. The internal resistance of a primary cell is 4 Omega . It generates a...

    Text Solution

    |

  2. A capacitor of 10 mu F has a potential difference of 40 V across it....

    Text Solution

    |

  3. The resistance of a conductor is 5Omega at 50^(@)C and 6Omega at 100^...

    Text Solution

    |

  4. In an electrical cable there is a single wire of radius 9 mm of copper...

    Text Solution

    |

  5. A copper wire of length l and radius r is nickel plated till its final...

    Text Solution

    |

  6. In the figure given below find the resistance between points A and B. ...

    Text Solution

    |

  7. The resistance of a wire of iron is 10 ohm and temperature coefficient...

    Text Solution

    |

  8. Drift velocity of electrons in a conductor bearing potential differen...

    Text Solution

    |

  9. 100 cells each of emf 5V and internal resistance 1 Omega are to be arr...

    Text Solution

    |

  10. The equivalent resistance of the hexagonal network as shown figure be...

    Text Solution

    |

  11. Twelve wires, each of resistance 1Omega are connected to form a skelet...

    Text Solution

    |

  12. In the network shown the potential difference between A and B is (R = ...

    Text Solution

    |

  13. Twelve equal wires each of resistance r Omega form a cube. The effect...

    Text Solution

    |

  14. The equivalent resistance between the terminals A and B in the network...

    Text Solution

    |

  15. 12 resistors each of 10Omega are connected as shown in the figure. The...

    Text Solution

    |

  16. In the network shown in figure each resistance is 1 Omega. The effecti...

    Text Solution

    |

  17. the length of wire of diameter 0.5 mm needed to produce a coil of resi...

    Text Solution

    |

  18. The resistance of a wire of length 40 m and radius o.25 mm is 10 Omega...

    Text Solution

    |

  19. A wire of resistance 12Omega is stretched uniformly till its length be...

    Text Solution

    |

  20. A wire of resistance 16Omega is bent in to a circle and a cell of e.m....

    Text Solution

    |