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the length of wire of diameter 0.5 mm ne...

the length of wire of diameter 0.5 mm needed to produce a coil of resistance `10Omega` and specific resistance `4.4xx10^(-7)Omega` m is

A

4.45 m

B

5.55 m

C

5.45 m

D

1.45 m

Text Solution

Verified by Experts

The correct Answer is:
A

`R= (rho l)/(A)`
`:.l=(10xx3.14xx25xx10^(-8))/(4.4xx10^(-7)xx4)=(78.5)/(17.6)=4.45`m
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