The resistance of a wire of length 40 m ...

The resistance of a wire of length 40 m and radius o.25 mm is `10 Omega`. The conductivity of the material of the wire is

`1xx10^( -7)` mho/m

`2xx10^(-7)` mho/m

`2xx10^(7)` mho/m

`1xx10^(-7)` mho/m

Text Solution

Verified by Experts

The correct Answer is:

`sigma = 1/rho=(l)/(RA)=(40)/(10xx3.14xx625xx10^(-10))`
`=2xx10^(7)` mho/m

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