A wire of resistance `16Omega` is bent in to a circle and a cell of e.m.f. 2V and internal resistance `1Omega` is connected between two points of wire, a quarter circumference apart. The current in each segment of wire is

Options

A. `8/1 A, 3/8 A`
B. `1/8 A, 8/3 A`
C. `8/1 A, 8/3 A`
D. `1/8 A, 3/8 A`

Answer

D

Explanation

`(i) I_(1)=((R_(2))/(R_(1)+R_(2)))I=(4)/(16)xx(V)/(R_(p))=(4xx2)/(16xx4)=1/8 A`
(ii) ` I_(2)=((R_(1))/(R_(1)+R_(2)))I=(12)/(16)xx (V)/(R_(p))=(12xx2)/(16xx4)=3/8 A`