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With resistances P and Q in the left gap...

With resistances P and Q in the left gap and right gap respectively, of a meter bridge. The null point is obtained at 60 cm from left end. When Q is increased by `10Omega` the null point is obtained at 40 cm from left end. The values of P and Q are

A

`12Omega, 8Omega`

B

`8Omega, 12Omega`

C

`8Omega, 8Omega`

D

`12Omega, 12 Omega`

Text Solution

Verified by Experts

The correct Answer is:
A
(i) `(P)/(Q)=(60)/(40) " " P=(3Q)/(2)`
(ii) `(P)/(Q+10)=(40)/(60)`
`(3Q)/(20+20)=2/4 " " 9Q=4Q+40 " " 5Q=40`
`:.P=(3xx8)/(2)=12Omega`
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