A resistance of potentiometer wire is 1O...

A resistance of potentiometer wire is `1Omega//m`. A Daniel cell of e.m.f. 1.08V balances at 216 cm on potentiometer. The current through wire is

1.5A

0.25A

2.5A

0.5A

Text Solution

Verified by Experts

The correct Answer is:

`E_(1)= I rho l_(1) " " :.I=(1.08)/(1xx2.16)=0.5 A`

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